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The molar heats of fusion and vaporization for water are 6.02 kJ/mol and 40.6 kJ/mol, respectively, and the specific heat capacity of liquid water is 4.18 J/g°C.
(a) What quantity of heat energy is required to melt 23.0 g of ice at 0°C?
kJ
(b) What quantity of heat is required to vaporize 34.5 of liquid water at 100°C?
kJ
(c) What quantity of heat is required to warm 53.9 g of liquid water from 0°C to 100°C?
kJ

2007-05-07 21:16:11 · 2 answers · asked by kevin 1 in Science & Mathematics Chemistry

2 answers

a)7.692 kJ

b) 77.82 kJ

c) 22.53 kJ

2007-05-07 21:28:50 · answer #1 · answered by ag_iitkgp 7 · 0 0

When in doubt in chemistry, always use dimensional analysis. Here is a basic outline on how to do all of these:
1) Convert grams to moles
2) If changing state, multiply moles by the molar heat of that change of state
3) If changing temperature within that state, multiply the heat capacity by the moles and temperature change.
This can all be figured out using dimensional analysis, even if you know nothing about chemistry

2007-05-07 21:30:44 · answer #2 · answered by TJBeatty 1 · 0 0

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