Word Problem (Dicey Differences) Help PLEASE?

Question

You are playing a new dice game. You roll two regular dice and then subtract the smaller number from the larger number. (If the dice show the same number, then it doesn't make any difference which way you subtract.) What is the difference most likely to occur?

Please explain each step!

Thanks!

Answer 1

there are 36 combinations of dies rolling differently.
Since larger number is divided by smaller number there are no negative numbers

if first die shows 6 the differences can be 5, 4, 3, 2,1,,0 { or other die showing 1 to 6 respectively}

if the first ie shows 5 hen he differences are 4 3 2 1 0 and 1

one could see that for numbers 5 to 2 on the first die gives
occurences of 1 twice for each numbe {from 5 to 2}

for first die showing 1 it is the same as in the case of first die showing 6 {i.e. 0 to 5}

so one could easily see that there are 10 occurences of
out of 36 possible.

THerefore 1 will be the answer in majority of the throws.

{probability 10/36}

in a graph take 1 2 3 4 5 6 as x ordinate - number which appears in the first die and mark in Y axis the ANTICIPATED difference for each of those numbers you will wasily see the ANSWER!

- thanks

Answer 2

It's similar to what you'd do with the traditional adding:

Make a 6 by 6 grid and fill in the differences. Then count squares for each difference between 0 and 5, the only possibilities. There are 36 squares. The ratio of the count to 36 gives the probability. The larget count is the most likely.

Answer 3

∆ , f
0 , 6*1 = 6
1 , 5*2 = 10
2 , 4*2 = 8
3 , 3*2 = 6
4 , 2*2 = 4
5 , 1*2 = 2