The 2'd and 3'd answerers are right, they supplement each other.
I can only add a formula for that velocity for the case of circular orbit (generally orbits are elliptical)
v = sqrt(G*M / R), G - the gravitational constant, M - the planet's mass, R - distance from the center of the planet to the orbiting body, i.e. radius of the orbit.
As you see, there is no mass of the orbiting body in the formula.
2007-05-08 04:44:33
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answer #1
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answered by Anonymous
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As the mass of small ball and the mass of the person are too small comparing to the mass of Earth, if the orbit is the same, the period and the speed will be the same. But if the ball mass would be as large as the Earth, this will be a different question: The BALL and the Earth would revolve around the barycenter and the period wold be shorter (the sum of masses isn't like the mass of the Earth alone.)
2007-05-07 18:43:19
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answer #2
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answered by Anonymous
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that's a belongings of orbits - gravitational tension, like a number of tension, applies acceleration that transformations your velocity. interior the case of the Moon, it pulls it in direction of the Earth particularly. although, the Moon additionally has a sturdy velocity by using area in a direction perpendicular to Earth - so as that's pulled in direction of Earth, its velocity consists of it away barely sufficient that the gap to Earth maintains to be consistent. The acceleration nevertheless has an effect, although, because of the indisputable fact that's continuously changing the *direction* of the Moon's velocity. there is all varieties of different thrilling issues happening interior the Moon's orbit, although - certainly, because of effect of Earth's tidal bulges on the Moon, that's slowly shifting removed from Earth (very, very slowly - an inch and a a million/2 each and every 365 days), and on the comparable time is slowing Earth's rotation down! (do no longer difficulty, although, the sunlight will develop right into a purple great long earlier this will become a situation.)
2016-12-17 07:07:24
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answer #3
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answered by Anonymous
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An object's mass has nothing to do with it's orbital speed.
Let's say you double the mass of an orbiting object. Then the force of gravity is twice as much. But then the object is twice as hard to move also. This exactly balances out so that mass makes no differerence.
2007-05-07 18:44:40
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answer #4
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answered by Demiurge42 7
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If they had the *same* mass, yes they would. In cases like this, size does *not* matter.
2007-05-07 18:28:01
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answer #5
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answered by Chug-a-Lug 7
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