can any one help me with tnis math probleam?

Question

make x the subject. 1 over x +3y =7b

Answer 1

1/(x+3y) = 7b

step 1: multiply both sides by (x+3y)
1 = 7b(x+3y)

step 2: divide each side by 7b
1/(7b) = x+3y

step 3: subtract 3y from each side
1/(7b) - 3y = x

Answer 2

That depends, do you mean (1/x) + 3y =7b or
1/ (x+3y) = 7b ? Another words, is all of x+ 3y in the denomonator, or does the problem just have the fraction 1 over x? Because they would give two different answers.

If its the first one, then subtract 3y from both sides, getting
1/x =7b-3y, then multiply both side by x, getting 1= (7b-3y)x
Then divide both sides by (7b-3y), getting the answer
x= 1/ (7b-3y).

If it's the second, then multiply both sides by (x+3y), getting
1= 7b (x+3y) which is the same as 1= 7bx+ 21by. Then
subtract 21by from both sides, getting 1-21by= 7bx. Divide both sides by 7b to isolate the x, getting the answer
x= (1-21by)/7b

Answer 3

If by making x the subject u mean make the equation equal to x, then...

1/x + 3y = 7b
1/x = 7b - 3y
1 = x (7b - 3y)
x = 1 / (7b - 3y)

Hope this helps!

Answer 4

you make x the subject by rearranging

1/(x+3y) = 7b (original)
1=7b *(x+3y) (multiply both sides by x+3y)
x+3y= 1/7b (divide both sides by 7b)

x=(1/7b)-3y (subtract 3y from both sides)

x is now the subject

Answer 5

only if x not equal to 0.
1/x + 3y = 7b
multiply both sides by x
1 + 3xy = 7bx
subtract 3xy from both sides
7bx - 3xy = 1
factor out x
x(7b-3y) = 1
divide both sides by 7b - 3y (also need b not equal to 3/7 y)
x = 1/(7b - 3y)

Answer 6

Assuming it is 1/(x+3y) = 7b

Then
x+3y = 1/(7b)
x = 3y - 1/(7b)
x = (21yb - 1)/7b

Alternatively - if it is (1/x) + 3y =7b
Then
(1/x) = 7b-3y
x= 1/(7b-3y)

Answer 7

1 / (x + 3y) = 7b
1 = 7b (x + 3y)
1 / 7b = x + 3y
x = (1 / 7b) - 3y

Answer 8

I have the same math and I cant even do it sorry ma I would help if I could.

Answer 9

sorry. math isn't my strongest subject