y=x^3+8 , Minimums, Maximums, X intercepts?

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y=x^3+8 , Minimums, Maximums, X intercepts?

What the hell? This graph has no minimums/maximums? MY GOD I'M GOING TO FAIL MATH.

2007-05-07 14:31:16 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help

3 answers

(-2,0) is the X-Intercept. I'm pretty sure that there are no minimums or maximums as well since the graph's Y and X values are all reals.

2007-05-07 14:42:22 · answer #1 · answered by monkeysofwar 3 · 1⤊ 0⤋

You are correct. There are no minimums and maximums. They are negative infinity and positive infinity, respectively.

To find x-intercepts, let y=0 and solve for x
0=x^3+8
x^3=-8
x=-2

2007-05-07 21:43:17 · answer #2 · answered by tkquestion 7 · 1⤊ 0⤋

minimums and maximums refer to turning points in parabolas (for quadratic formulae)

and let y=0 to find the x-intercept

2007-05-07 21:53:05 · answer #3 · answered by Billy 5 · 0⤊ 0⤋