How do I predict the entropy sign of this reaction?

Question

NO(g) + O3(g) ------> NO2(g) + O2(g)

usually I would look for the phase changes etc. to figure out the sign (+ or -) of the entropy change, but in this reaction molecules arent breaking into smaller pieces, and there are the same number of moles gas on either side....
Can anyone help?
Thanks

Answer 1

Zero, no change in phases.

Answer 2

a) formation of one molecule lead chloride from 2 molecules, ability a lot less randomness, then there's a decrease in S; meaning delta S is unfavourable b) formation of two molecules from one molecule of CaCo3, ability more effective randomness, then there is an enhance in S; meaning delta S is effective c) formation of four molecules from 2 molecule of reactants, ability more effective randomness, then there is an enhance in S; meaning delta S is effective d)formation of one molecule from 4 molecules of reactants, ability a lot less randomness, then there's a decrease in S; meaning delta S is unfavourable e) formation of 8 molecules from seven molecule of reactants, ability more effective randomness, then there is an enhance in S; meaning delta S is effective f) as a effect, one molecule is reactant and one is product, in spite of the indisputable fact that the product is a gas, and gas has more effective randomness than good or liquid, then there is an enhance in S; meaning delta S is effective.