log(a) + log(b) = log(a*b)
So presumably the answer you are expected to give is log(7) + log(2) = log(7*2) = log(14).
log(14) = 1.146128 or so.
2007-05-07 13:35:50
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answer #1
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answered by McFate 7
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log 7 = 0.845
log 2 = 0.301
the sum = 1.14 6
The log of 7 = log of 2 is not equal to log 7 * log 2
as someone stated. When you add to logs it means you are adding the two logs of the original numbers to perform a multiplication. In this case if you take the antilog of 1.146 you well get 14 which is obviously 7 * 2.
2007-05-07 13:38:25
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answer #2
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answered by Anonymous
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well rules of logs say.. if you are adding you are multiplying
which means
log 7 + log 2 = log 7 * log 2
since the bases are the same (10) you can put then under 1 log
i.e. Log 7*2 = Log 14 which is approximately 1.15 (3 sig figures)
2007-05-07 13:38:03
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answer #3
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answered by sudhi_kandi 3
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Property of of logs
log x + log y = log xy
log 7 + log 2 = log 14
2007-05-07 13:36:46
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answer #4
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answered by Anonymous
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log7 + log2 = log(7)(2) = log14
2007-05-07 13:36:08
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answer #5
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answered by Scott2Hott 2
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Mult, log 14
2007-05-07 13:35:59
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answer #6
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answered by richardwptljc 6
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log7 + log2=log14==1.146. answer
2007-05-07 13:51:07
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answer #7
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answered by Anonymous
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i am sure your computer has calculator.
2007-05-07 13:35:32
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answer #8
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answered by ۞_ʞɾ_ 6
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1.1461
2007-05-07 13:37:45
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answer #9
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answered by Anonymous
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