if sin=3/5 what is cos,tan,csc, sec,cot?

Answer 1

picture the right triangle, vertical side 3,hypotenuse 5 (since sin = 3/5). then horizontal side is 4, and

cos = 4/5
tan = 3/4
csc = 5/3
sec = 5/4
cot = 4/3

Answer 2

Sin = opposite over hypotenuse. If one side is 3 and the hyp = 5, then the other side = sqrt(5^2 - 3^2) = sqrt(25 - 9) = sqrt(16) = 4

So cos = 4/5
tan = 3/4
sec = 1/cos = 5/4
csc = 1/sin = 5/3
cot = 1/tan = 4/3

Answer 3

Remember that:
sin^2 (x) + cos^2 (x) = 1
tan(x) = sin(x) / cos(x)
csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
cot(x) = 1/tan(x)

So using the fact that sin(x) = 3/5, you can find cos(x) with the first identity, then use the definitions above to find the other trig function values.

Answer 4

Draw your reference triangle. You know that sine is y/r.

When you draw your reference triangle, r is the hypotenuse. You get these values:

x = 4
y = 3
r = 5

Here:

cos = x/r
tan = y/x
csc = r/y
sec = r/x
cot = x/y

Answer 5

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