How would you simplify:
10y^2 + 15y (over) 35y^2 - 5y
not just the answer, but also how you got it. and no dumb answers, k thanks.
2007-05-07 12:02:35 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
gah i need help again, can anyone also answer this question:
x^4 + x^3 - 2x^2 (over) x^4 - x^3
2007-05-07 12:21:36 · update #1
10y² + 15y
-------------- =
35y² - 5y
5y(2y + 3)
-------------- =
5y(7y - 1)
2y + 3
---------
7y - 1
2007-05-07 12:12:05 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
10y^2 + 15y) / 35y^2 - 5y
divide by 5y, which is a common factor
2y + 3/7y - 1
2007-05-07 19:14:18 · answer #2 · answered by falconrf 4 · 0⤊ 0⤋
(10y^2 + 15y)/(35y^2 - 5y)
Factor out 5y out of both the numerator and denominator.
(2y + 3)/(7y - 1)
.
2007-05-07 19:12:28 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
(10y^2+15y)/(35y^2-5y)
={5y(2y+3)}/{5y(7y-1)
=(2y+3)/(7y-1) ans
2007-05-07 19:11:33 · answer #4 · answered by alpha 7 · 0⤊ 0⤋