algebra 2 help!?

Question

problem 1: simplify your answer i^6=
problem 2: solve | 7x-2 | = x+5
problem 3: divide (2x^3+7x^2-5) divided by (x+3)
problem 4: logarithmic and exponential functions are a) even functions b) odd functions c) composite functions d) inverse functions

problem 5: Expand the binomial expression, using the binomial theorem (x+y)^3

problem 6: write 16x^2+4y^2+96x-8y+84=0 in standard form

problem 7: three residents are to speak at the next city council meeting the order in which they will speak needs to be decided. how many different orders can they speak?

problem 8: find the sum of the first 100 counting numbers

problem 9: solve (4x+3/x-1) - (4x-3/x1) = (10/x^2-1)

problem 10: a ball thrown vertivally upward with an initial velocity of 20 feet per second is represented by the equation h=-16t^2+20t. (h=height in feet, t=time in seconds) After 1 second what is the height of the ball?

Answer 1

1)
i^6 = i^4 * i^2 = (1)(-1) = -1

2)
7x - 2 = x + 5 OR 7x - 2 = -(x + 5)
6x = 7 OR 8x = -3
x = 7/6 OR x = -3/8

3)
2x^2 + x - 3 + 4/(x+3)

5)
x^3 + 3x^2 y + 3xy^2 + y^3

6)
16x^2 + 96x + 4y^2 - 8y = -84
16(x^2 + 6x) + 4(y^2 - 2y) = -84
16(x^2 + 6x + 9) + 4(y^2 - 2y + 1) = -84 + 16(9) + 4
16(x + 3)^2 + 4(y - 1)^2 = 64
(x+3)^2 / 1 + (y-1)^2 / 4 = 4

7)
3! = 3*2*1 = 6

8)
1 + 100 = 101
2 + 99 = 101
3 + 98 = 101
.....
49 + 51 = 101
That's 49 pairs of 101, plus 50 which didn't have a pair.

So... 49(101) + 50 = 4999

9) I assume you meant:
(4x + 3)/(x - 1) - (4x - 3)/(x+1) = 10/(x^2 - 1)
Factor the denominator on the right of the = sign
(4x + 3)/(x - 1) - (4x - 3)/(x+1) = 10/(x-1)(x+1)
Multiply everything by (x-1)(x+1)
(x+1)(4x+3) - (x-1)(4x-3) = 10
4x^2 + 7x + 3 - (4x^2 -7x + 3) = 10
14x = 10
x = 5/7

10)
h = -16t^2 + 20t
plug in t = 1
h = -16 + 20 = 4 feet

Answer 2

First of all, hon, if you have this many problems understanding your homework, talk to your teacher. I will get you started on some.

1) i^2 = -1
i^6 = (i^2)(i^2)(i^2)

2) -(7x - 2) = x + 5 or (7x - 2) = x + 5
-7x + 2 = x + 5 or 7x - 2 = x + 5

4) Exponential are logarithmic functions are inverse functions. The exponential function is an inverse of the logarithmic.

6) Get the y terms on one side, the x terms on the other side, and divide everything by 4, since it's a common factor.

7) Any of the three may speak first. The second speaker will be either of the other two. The third speaker can only be the one that's left.

8) sum =
1 + 100 +
2 + 99 +
3 + 98 +
.....
49 + 52 +
50 + 51
= 50(101)

10. t = 1
h = 16(t^2) + 20(t)
h = 16(1^2) + 20(1)

Answer 3

For increasing cubic binomials the final formulation is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D

Answer 4

no one's going to do your homework for you
we have enough of our own