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a wheel with a rasius of 15 cm is spinning at 12 revolutions per sec. what is the linear speed of the belt that is wrapped around the outside of the wheel?

help please? idk how to solve

2007-05-07 10:37:25 · 3 answers · asked by edger 1 in Science & Mathematics Mathematics

3 answers

If the radius is 15cm, the circumference is 15*2*pi, or about 94.25cm.

If the wheel is spinning at 12 revolutions per second, then every second a length of belt equal to 12 times the circumference is moved.

The belt speed would be 12*c = about 1,131 cm/sec

The respondent who used "pi r^2" is confused, or trying to confuse you. An equation with pi * r^2 will give the area of the wheel and has nothing to do with its radial speed. (The units would be area/time which is not distance/time that speeds are expressed in.)

2007-05-07 10:42:21 · answer #1 · answered by McFate 7 · 0 0

Don't believe these guys trust me its 2PiR^2 so it would be (12)(2Pi)(15^2)

The answer is: 16964.600329384883487698274269709 You could round this to whatever you like

2007-05-07 17:59:03 · answer #2 · answered by lord_andys_new_id 1 · 0 1

v = rθ' = 15 (12)(2pi) = 1130.97 cm/sec

2007-05-07 17:46:04 · answer #3 · answered by sahsjing 7 · 1 0

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