(√2 + 7)^2?

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2007-05-07 10:12:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Square the term, and use the cross multipliers.
(2^(1/2)+7)(2^(1/2)+7) = 2^(1/2 + 1/2) +14*2^(1/2)+49

or 2^1 + 14*2^(1/2) + 49 = 14*2^(1/2)+51

2007-05-07 10:20:28 · answer #1 · answered by Anonymous · 0⤊ 0⤋

(â2 + 7).(â2 + 7)
= 2 + 14â2 + 49
= 51 + 14â2

2007-05-07 18:04:53 · answer #2 · answered by Como 7 · 0⤊ 0⤋

Use the binomial theorem: (a+b)^2 = a^2 + 2ab + b^2 =
2 + 14 sqrt(2) + 49 = 51+14sqrt(2).

2007-05-07 17:35:13 · answer #3 · answered by Paul R 2 · 0⤊ 0⤋