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6 answers

sqrt(22) x sqrt(44) =

sqrt(22x44) =

sqrt (11x11x2x4)=

11x2xsqrt(2) =

22sqrt(2)

2007-05-07 10:12:16 · answer #1 · answered by ? 3 · 0 0

= √ (22 x 44)
= √ 968
= √ (8 x 121)
= 11 √ 8
= 11 x 2.√ 2
= 22.√ 2

2007-05-07 11:27:20 · answer #2 · answered by Como 7 · 0 0

In the solution assume "sqr.rt" as square root and the symbol " ^ " as power or exponent.

sqr.rt 22 * sqr.rt 44
given expression

sqr.rt ( 22 * 44)
product of two sqr.rt can be written as a single sqr.rt

sqr.rt (2*11*2*2*11)
splitting 22 and 44 into smallest possible factors.

sqr.rt (2*2*2*11*11)
arranging the numbers

sqr.rt (2^2 * 11^2 * 2)
writting a pair in exponent form

sqr.rt (2^2) * sqr.rt (11^2) * sqr.rt (2)
splitting single sqr.rt into many sqr.rt

2 * 11 * sqr.rt (2)
sqr.rt and power 2 cancel each other

22 sqr.rt 2
final answer

2007-05-07 10:53:37 · answer #3 · answered by nido 2 · 0 0

You multiple radicals like any number

Multiple 22 and 44 together to get √968
Then try to think of the largest perfect square that goes into 968.... 484 and 2
So now you have: √484 * √2
Since √484 is a perfect square, you can reduce it to 22. √2 is not a perfect square, so you leave it as √2

So the answer is 22√2

2007-05-07 10:17:47 · answer #4 · answered by orlandoluvr_1990 3 · 0 0

sqrt(66)=sqrt(3*22) so
sqrt(22)*sqrt(66) = sqrt(3*22*22)
= 22*sqrt(3)

2007-05-07 10:15:02 · answer #5 · answered by Anonymous · 0 0

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2007-05-07 10:12:56 · answer #6 · answered by Anonymous · 0 0

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