x^2 - 9
2007-05-07 08:51:26
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answer #1
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answered by Britt L 2
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The rule is first, outer, inner, last : first: x times x = x2
outer: -3 times x = -3x
inner: 3 times x = 3x
last : 3 times -3 = -9
add together = x2+3x+(-3x) -9 = x2-9
2007-05-07 15:53:42
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answer #2
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answered by CHRISTOPHER C 4
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this is similar to multiplying by x(x-3) just with another number 3.. so,
using distributive property, forget foil..it only works for binomial with binomial, and distributive works for any combination.
so here
x(x-3) + 3(x-3)
x^2-3x +3x-9
simplifying,
x^2 -9
2007-05-07 16:00:29
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answer #3
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answered by JAC 3
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x^2 - 9
2007-05-07 15:51:48
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answer #4
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answered by ulfsnilsson 2
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x^2-9
2007-05-07 16:53:27
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answer #5
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answered by Anonymous
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This is a very common problem. If you can not do it you are in big trouble. You must be able to reverse the process in factoring. Note how x^1 cancel out. The other numbers are ^2.
2007-05-07 16:03:06
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answer #6
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answered by Richard F 7
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x^2-9
2007-05-07 15:52:33
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answer #7
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answered by Dave aka Spider Monkey 7
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FOIL( first, outer, inner, last)
(x+3)(x-3)
F: x times x = x2
O: x times -3 = -3x
I: 3 times x = 3x
L: 3 times -3 = -9
then when you get that, you have to add O & I. therefore
-3x plus 3x =0
thus you are left with x2 and -9 only.
so your answer would be: x2 -9
good luck with math. practice makes perfect. a good teach who knows how to explain would also be helpful.. LOL
2007-05-07 15:59:50
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answer #8
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answered by annlyvqp 3
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Use the F.O.I.L. method (First, Outside, Inside, last)
x^2 -3x +3x - 9
x^2 - 9
2007-05-07 15:52:21
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answer #9
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answered by Anonymous
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x²-9
You use FOILing (First, Outside, Inside, Last)
(x+3)(x-3)
x(x)+x(-3)+3(x)+3(-3)
I hope I explained it well enough!
2007-05-07 15:56:23
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answer #10
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answered by sheritta n 2
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