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surds

2007-05-07 07:15:04 · 11 answers · asked by Arn 1 in Science & Mathematics Mathematics

11 answers

root 4 is 2, because 4 = 2*2

so root 3 * root 4 = 2 root 3

2007-05-07 07:19:49 · answer #1 · answered by Anonymous · 0 0

root 3 * root 4=root 12=2 root 3

2007-05-07 08:48:33 · answer #2 · answered by Dave aka Spider Monkey 7 · 0 0

Do you mean sqrt(3) * sqrt(4)? This could also be written as sqrt(12) because when multiplying radicals, you can multiply the numbers inside the roots and put them under one radical.

If so, the sqrt(4) = 2 so it's 2 * sqrt(3)
sqrt(3) is a decimal and can't be simplified.

the answer would be 2sqrt(3)

2007-05-07 07:20:55 · answer #3 · answered by JirafaBo 2 · 0 0

2 root 3

square root of 4=2

how ever if by some strange reason you mean root 3 to the power of root 4 then it is just 3

i have made that typo before and not realized it

2007-05-07 07:24:45 · answer #4 · answered by Anonymous · 0 0

hiya BH70 The sq. root of three/4 is comparable to ?(3/4), that is comparable to ?3 ÷ ?4, which, equals ½?3. So, what's the sq. root of three? it is: a million.73205 08075 68877 29352 74463 41505 87236 69428 05253 81038 .... One 0.5 of ?3, that's the quantity for which you're querying, is: 0.86602 54037 84438 64676 37231 70752 93618 34714 02626 90519 .... answer: 0.86602 54037 84438 64676 37231 70752 93618 34714 02626 90519 ....

2016-10-15 00:39:13 · answer #5 · answered by ? 4 · 0 0

1 1 1* root 1 1 1 1 surds back

2007-05-07 07:20:32 · answer #6 · answered by Jewel 6 · 0 2

root 3 * root 4 = root 3 X 4 which is 2root3

2007-05-07 07:37:25 · answer #7 · answered by Anonymous · 0 1

=√ 3√ 4
=√ (3*4)
=2√ 3

OR
=√ 3√ 4
=√ (3*4)
= ± 2√ 3

2007-05-07 07:33:57 · answer #8 · answered by harry m 6 · 0 0

Sqrt (3) * Sqrt (4) = Sqrt (12)
= Sqrt (2 * 2 * 3)
= 2 Sqrt (3)

Hope this helps and if it does vote for it!!

2007-05-07 08:31:43 · answer #9 · answered by Anonymous · 0 0

Two possible answers

(a) root12

(b) since root4 = 2,

2root3

If this was an exam question, I think that I would go with (b)

2007-05-07 07:25:36 · answer #10 · answered by fred 5 · 0 0

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