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help please I am totally lost :(

2007-05-07 06:44:45 · 7 answers · asked by Anonymous in Science & Mathematics Physics

7 answers

Note that the resistance from the calculation of 9.0V / 7.8mA is only valid while the lamp is energized. If you read the resistance of the lamp filament with an ohmmeter, you will find that the resistance is much lower. This is due to the temperature coefficient of the lamp element.

JeffM

2007-05-07 06:50:49 · answer #1 · answered by Jeff M 3 · 0 0

V=I*R
here I=.0078 A
V=9.0 V
So R=9.0/.0078
=1153.85 Ohm(approx)

2007-05-07 06:52:03 · answer #2 · answered by paramita d 1 · 0 0

U=9.0 V
I=.0078 A
R=U/I=9/.0078=1153.846 ohms

2007-05-07 06:48:47 · answer #3 · answered by fanda 2 · 0 0

Ohm's Law: V = I x R
where:
V- voltage (in Volts)
I - Current (in Amperes)
R- resistance (in Ohms)

so 9.0 = .0078 x R

R = 9.0 / .0078 = 1153.84 ohms approximately 1154 ohms

2007-05-07 06:50:23 · answer #4 · answered by Anonymous · 0 0

You need to use Ohm's Law, V = IR

V = voltage (measured in volts)
I = current (measured in amps)
R = resistance (measured in Ohms)

Since you're looking for resistance, solving Ohm's Law for R, R= V/I = 9.0V/0.0078A = about 1153 Ohms

2007-05-07 06:51:26 · answer #5 · answered by hairylunch 1 · 0 0

R = V/I = 9/0.0078 = 1153.8 Ohms

2007-05-07 06:57:32 · answer #6 · answered by Swamy 7 · 0 0

V=IR,
R=V/I
R=9/.0078
R=1,153.8 ohms
or 1.15 Kohms

2007-05-07 06:49:06 · answer #7 · answered by Anonymous · 0 0

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