Dave's watch is three minutes slow but he thinks it is five minutes fast.
John's watch is seven minutes fast but he thinks it's three minutes slow.
Lee's watch is five minutes slow but he thinks it's nine minutes fast.
Rob's watch is nine minutes fast but he thinks it's the exact time.
If they plan to go to a common friend's house at six o'clock and they leave at the same time, who would be at the friend's house first?
2007-05-07 04:51:36 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
key: + means fast, and - means slow
dave (-3, but thinks +5) plans to go when his watch 6:05, but he'll get there at 6:08.
john (+7, but thinks -3) plans to go when his watch says 5:57, but gets there at 5:50.
lee (-5, but thinks +9) plans to go when his watch says 6:09, but ends up being there at 6:14.
rob (+9, but thinks 0) plans to go when his watch says 6, but arrives at 5:51.
so, john.
the friend was probably steamed.
2007-05-07 13:43:52 · answer #1 · answered by Ənigma 2 · 0⤊ 0⤋
Dave's watch is three minutes slow but he thinks it is five minutes fast. So he will plan to get there wneh his watch says 6:05, actually getting there at 6:13
John's watch is seven minutes fast but he thinks it's three minutes slow so he plans to arrive at 5:57 but gets there at 5:50
Lee's watch is five minutes slow but he thinks it's nine minutes fast. Plan to arrive: 6:09; actually, 6:14
Rob's watch is nine minutes fast but he thinks it's the exact time. Plan 6:00; arrive 5:51.
So John
2007-05-07 12:08:18 · answer #2 · answered by hayharbr 7 · 3⤊ 0⤋
Nevermind
2007-05-07 12:01:24 · answer #3 · answered by Anonymous · 0⤊ 2⤋
Rob
2007-05-07 11:59:39 · answer #4 · answered by hagridxxxx 3 · 0⤊ 2⤋
rob
2007-05-07 12:00:02 · answer #5 · answered by Vann M 2 · 0⤊ 2⤋
whoever lives the closest.
2007-05-07 11:59:30 · answer #6 · answered by j c 4 · 2⤊ 2⤋