2007-05-07 03:40:15 · 16 answers · asked by ASH M 1 in Computers & Internet ➔ Hardware ➔ Desktops
effectiveness, reliability, price
2007-05-07 03:42:59 · answer #1 · answered by Splishy 7 · 0⤊ 0⤋
the industry is based on dishonest people writing viruses, why does a antivirus company not pay people to write these viruses so they can make even more profits. i have a virus on this computer that is an advert from a 'antivirus' company i have to pay money to get rid of it!
2007-05-07 03:57:00 · answer #2 · answered by j_emmans 6 · 0⤊ 0⤋
You should be looking for one that protects your computer the most. There are lots of different brands out there. Get a good one before you run into bother and make sure you upgrade each year. New viruses are always coming out.
2007-05-08 02:25:51 · answer #3 · answered by Black 7 · 0⤊ 0⤋
Difference to what?
An antivirus scanner scans for virus's.
2007-05-07 03:43:33 · answer #4 · answered by Gone Fishing 4 · 0⤊ 0⤋
They use different scanning engines and different methods to detect virus, so sometime one would find one while another misses, but all the major ones are normally covered with the latest updates.
2007-05-07 03:44:03 · answer #5 · answered by Cupcake 7 · 0⤊ 0⤋
The free ones normally have the same core components as the Professional ones .
2007-05-07 23:12:51 · answer #6 · answered by D G 6 · 0⤊ 0⤋
Get Webroot Spy Sweeper w/ anti virus
2007-05-07 03:45:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Price, detection performance, features. Probably.
2007-05-07 03:48:52 · answer #8 · answered by csd172 2 · 0⤊ 0⤋
It is impossible to say.
The only certainty is that they do not offer a guarantee to protect your computer against viruses.
2007-05-07 04:52:07 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Difference in what?
2007-05-07 04:07:07 · answer #10 · answered by simonjohnlaw 5 · 0⤊ 0⤋
Hello:
I recommend AVAST it is free and does the job.
You can get it from AVAST.com and it last for 14 mos.
before you have to register it.
FW
2007-05-07 03:46:57 · answer #11 · answered by freedom w 1 · 0⤊ 0⤋