Simplify fully...?

Question

Simplify:
(2t^3u) x (3tu^2)

^3 = cubed
^2 = squared

Answer 1

(2 t³ u)(3 t u²) =

6 t⁴ u³

- - - - - - - -s-

Answer 2

(2t^3u) x (3tu^2)

I’m not certain if there is an x factor in the middle, but I will presume there is not. With that in mind, I will be working with
(2t³u)(3tu²)

There are properties, “rules” if you will, that you absolutely need to know…
For any a, b, and c in the set of real numbers
ab=ba (commutative property of multiplication – there’s one for addition too)
(ab)c=a(bc) (associative property of multiplication – there’s also one of these for addition.
There are a few others, but these are the ones you need to know for this problem.

Because of these properties
(2t³u)(3tu²)=[(2)(3)][(t³)(t)][(u)(u²)]
2 x 3 = 6 where, in this case (and the next two) x means “times”
t³ x t = t^4…. Sorry no symbols for exponents over 3
u x u² = u³
so
(2t³u)(3tu²)=[(2)(3)][(t³)(t)][(u)(u²)]
= 6(t^4)(u^3)

Answer 3

(2t^3u) * (3tu^2)
= (2*3) * (t^3 * t) * ( u* u^2)
= 6 * (t^(3+1)) * (u^(1+2))
=6* (t^4) * (u^3)
=6(t^4)(u^3)

Answer 4

it canbe solved so that:
2 x ( t^3 ) x ( u ) x 3 x t x ( u^2 )
u = u^1
t = t^1
also:
( 2 x 3 ) x [ t^( 3 + 1 ) ] x [ u^( 1 + 2 ) ]
now
6 x ( t^4 ) x ( u^3 )
as a result

Answer 5

6t^4u^3

all you have to do is multiply it like it is a regular multiplication problem. When you multiply in another variable, it just adds to exponent. If you were to go ahead and factor it, you would end up with the problem that you started with.

Answer 6

= 6.t^(4).u^(3)

Answer 7

I get the same as everyone else

Answer 8

the same 6t^4u^3