How would you factorise this and what is the answer??
12q^2 r^3 - 24q^2 r + 30q^3 r^4
(The gaps are for easier reading)
2007-05-07 02:48:43 · 5 answers · asked by Peter 2 in Science & Mathematics ➔ Mathematics
All terms can be divided by 6, by q^2 and by r, so take 6q²r out as a factor
Giving
6q²r(2r² - 4 + 5qr^3)
2007-05-07 02:58:03 · answer #1 · answered by joncummins1968 4 · 0⤊ 0⤋
Hello
First thing to do is factor our a common factor of 6q^2 r
Thus you have: 6q^2 r(2r^2 - 4 + 5qr^2)
Now we check to see if we can factor the trinomial of 2r^2-4+5qr^2.
There is no "real" way to factor this. So the solution is
6q^2 r(2r^2 - 4 + 5qr^2).
Hope this helps
2007-05-07 09:57:24 · answer #2 · answered by Jeff U 4 · 0⤊ 1⤋
the same: first you have to see the minimum repated terms, q, r, then the comon factor to 12,24,30 which is 6:
6q^2r (2r^2-4+5qr^3)
2007-05-07 10:10:22 · answer #3 · answered by Anonymous · 0⤊ 0⤋
6q^2r(2r^2-4+5qr^3)
"factorize" is not a word.
factor is the word!
2007-05-07 10:06:47 · answer #4 · answered by rwbblb46 4 · 0⤊ 0⤋
12q²r³ - 24q²r + 30q³r⁴
6q²r(2r² - 4 + 5qr³)
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2007-05-07 10:23:30 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋