4n^2+20n-200,000?

Question

what does n equal. i cant find my calculator

its a quadratic

Answer 1

That's not an equation, so you can't determine n. You could factor that quadratic. Or you could solve it as if "4n^2+20n-200,000 = 0". But lacking "= [some value]" you can't determine n.

Assuming it is "=0", just use the quadratic:

n = (-20 +/- sqrt(20^2 - 4*4*(-200,000))) / (2*4)
n = (-20 +/- sqrt(3,200,400))/8
n = (-20 +/- 60 sqrt(889)) / 8
n = -5/2 +/- 15/2 sqrt(889)

This also gives you the factoring. That equation, factored, is:

4 (n - 5/2 - 15/2 sqrt(889)) (n - 5/2 + 15/2 sqrt(889))

Answer 2

No answer for n because what you've written is not an equation. See there is no equal sign. But if we equate it to zero, then it is a quadratic equation where the value of n could be determined. The general formula is:
an^2 + bn + c = C. If C =0 then the formula is simplified as,
n =[ -b +/-the square root of b^2-4ac]/2a
where a = 4, b = 20, c = -200,000

Solving n:
n = [-20 +or- the square root of {20^2-4(4)(- 200000)}]/2(4)
n = (-20 +or- the square root of 3,200,400)/8
n = (-20 +or- 1789)/8

Two answers:
1. n = (-20 + 1789)/8 = 221
2. n = (-20 - 1789)/8 = -226

Answer 3

You can't solve it if there's no equal. If it was 4n 2 +20n-200,000=0 you would get the answer 49,995.
You need to have the whole question right to get the right answer. I hope this helped out!

Answer 4

if you want to determine n you need what the equation equals. no wonder you can find the answer. ther isn't one.