writing as quadratic expression?

Question

4x^2 - 8x +16 = 0
(x ? ) (x ? )

what do i do with 4 infron of the x squared,
what would both the x values equal too?

Answer 1

4x^2 - 8x +16 = 0

First divide both sides of the equation by 4.

Then
x² - 2x + 4 = 0

then solve with the quadratic equation

x = (-b +- √(b² -4ac))/2a

x = (2 +- √(4 -16))/2

x = 1 + i√3, 1 - i√3,

.

Answer 2

you can either leave it there if all the other coefficients are not divisible by 4 or if they are divisible by four like the one you have given.

factorize

4(x^2 - 2x + 4) = 0
the four can be ignored, if u wanna know why, you move the four to the right 0/4 is still zero.

now u see u cant just find the root by factoring.
u must use the formula or complete the square..
(the formula is derived from completing the square methd)

ill complete the square.

(x - 1)^2 + 4 - 1 = 0
(x - 1)^2 = -3

x = 1 + sqrt(3)*i or 1 - sqrt(3)*i
they are complex numbers.

Answer 3

You can factor the 4 out then
4x^2 - 8x +16 = 0
4(x^2 -2x +4)=0
(x^2 -2x +4)=0
(x-1)^2 + 4 - 1 = 0
(x-1)^2 = -3
x-1 =+ isqrt(3), - isqrt(3)
x = 1 + isqrt(3), 1 - isqrt(3)

Answer 4

divide both sides by 4

x^2 - 2x + 4 = 0
complete the square:
x^2 - 2x + 1 - 1 + 4 = 0
(x - 1)^2 + 3 = 0
(x - 1 + 3i)(x - 1 - 3i) = 0
x = -1 +/- 3i
x is an imaginary number

Answer 5

remember this,

aX^2 + bX + c = 0

for a quadratic equation(polynomial order 2nd) the roots of the equation are:



X = -b + ( ( ((b)^2)-4ac) )^1/2 )/2a

X = -b - ( ( ((b)^2)-4ac) )^1/2 )/2a

my notations are a bit messy,look at wikipedia..

so the answers should be :

X = 8 + ( ( 64 - 4*4*16 )^1/2 ) / (2*4) = 1 + (3^1/2)j

X = 8 - ( ( 64 - 4*4*16 )^1/2 ) / (2*4) = 1 - (3^1/2)j

Answer 6

Sorry, complex numbers:

4x^2 - 8x + 16 = 0

Then:
x1 = 1 + SQR(3)*i
x2 = 1 - SQR(3)*i

So: 4x^2 - 8x + 16 = 4*(x-1-sqr3*i)*(x-1+sqr3*i)

Where SQR means Square Root

Answer 7

To begin with, you can simplify the equation by dividing it by 4:

x^2 - 2x + 4 = 0

Now x= (2 +- sqrt(2^2 - 4*1*4))/2
x = (2 +- sqrt(-12))/2
x = 1 +- sqrt(-3) = 1 +- i*sqrt(3)

(Both solutions are complex)

Answer 8

a million. x^2 + 5x + 4 (x + 4)(x + a million) 2. x^2 + 6x + 8 (x + 4)(x + 2) 3. x^2 -7x + 10 (x - 5)(x -2) 4. x^2 + 7x x(x + 7) x = 0 x = -7 5. x^2 +5x - 6 (x + 6)(x - a million) 6. 2x^2 -5x - 12 (2x + 3)( x - 4) 7. x^2 -7x -8 (x + 8)(x -a million) 8, x^2 - 5x x(x - 5) x = 0 x = 5

Answer 9

x= 1 (+/-) i√3.
can be solved by using x=[-b(+/-)sqrt(b^2-4*a*c)]/(2a)
x turns out to be imaginary.