Please help me with this Inorganic Chemistry question!
:)
Use the Valence Shell Electron Pair Repulsion Theory (VSEPR) stating any rules used to predict the shape of the molecular ion, iodine tetrabromide. Draw its structure and comment on any bone angle and bond legth variations you might expect in this molecular ion.
(i couldn't figure out the bonding process, Iodine and 4 x Bromine all have 7 valence electrons?)
2007-05-06 21:41:51 · 3 answers · asked by soshsiao 2 in Science & Mathematics ➔ Chemistry
As always ag is correct & the hybidisation is sp3d2. The structure is square planar. & as for drawing of structure, its impossible here. The bond angles & bond length of a sp3d2 ie. hexagonal bipyramidal structure can be found in any std. book. There are 2 two lone pairs at the two apexes of the bipyramid.
2007-05-06 23:09:34 · answer #1 · answered by s0u1 reaver 5 · 0⤊ 0⤋
I would say that this is a tetrahedral molecule with four bromine atoms attached to an iodine at the center. The bonds would be longer than carbon bromine bonds due to the large electronegativities of both iodine and bromine. The bonds would be weak. The angles would be similar to an sp3 hybridized carbon molecule.
2007-05-07 04:57:49 · answer #2 · answered by stacy 2 · 0⤊ 0⤋
IBr4, Square planar, sp3d2
2007-05-07 05:30:38 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋