2007-05-06 19:52:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
d/dx((x^2+3)^2)
=2.(x^2+3).d/dx(x^2+3)
=2.(x^2+3).(2x+0)
=4x.(x^2+3) ans
2007-05-06 20:37:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(x^2 + 3) ^2 = x^4 + 6x^2 + 9
and the derivative of that is
4x^3 + 12x
2007-05-06 20:06:26 · answer #2 · answered by sele84 1 · 0⤊ 0⤋
(x^2+3)^2=x^4+6x^2+9
So derivative=d/dx(x^4+6x^2+9)
=4x^3+12x
2007-05-06 20:08:20 · answer #3 · answered by paramita d 1 · 0⤊ 0⤋
2*2x*(x^2 + 3)
=4x*(x^2 + 3)
2007-05-06 19:57:06 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
Method 1
f(x) = (x² + 3)²
f ` (x) = 2.(x² + 3).(2x)
f ` (x) = 4x.(x² + 3)
f ` (x) = 4x³ + 12x
Method 2
Let y = (x² + 3)²
Let u = x² + 3
du/dx = 2x
y = u²
dy/du = 2u
dy/dx = (dy/du).(du/dx)
dy/dx = (2u).(2x)
dy/dx= 2(x² + 3).2x
dy/dx = 4x.(x² + 3)
dy/dx = 4x³ + 12x
2007-05-06 22:51:18 · answer #5 · answered by Como 7 · 0⤊ 0⤋