2007-05-06 19:01:33 · 4 answers · asked by D1e 2 in Science & Mathematics ➔ Mathematics
Let s = sinx
Your equation will be
4s^2 +4s - 3 = 0
which you should recognise as a quadratic.
It will factorise to give you the roots call them a and b
You then just solve sinx = a and sinx = b for whatever range of x you have been given or else state the general solution if no range supplied
2007-05-06 19:10:34 · answer #1 · answered by fred 5 · 3⤊ 0⤋
4sin^2x+4sinx-3=(2sinx-1)(2sinx+3)=0 since -1
2007-05-07 02:29:35
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answer #2
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answered by Ahmad k 2
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(2 sin x + 3).(2sin x - 1) = 0
sin x = - 3 / 2, sinx = 1/2
sinx = 1/2 is acceptable (sinx ⤠1)
x = 30° , x = 150°
2007-05-07 03:07:47 · answer #3 · answered by Como 7 · 0⤊ 0⤋
Did you need the problem Factored?
here goes!
[2sin(x)-1] [2sin(x)+3]
2007-05-07 02:11:07 · answer #4 · answered by frizzball2me 1 · 0⤊ 0⤋