2007-05-06 17:54:40 · 6 answers · asked by willsatx 1 in Science & Mathematics ➔ Mathematics
x+4y = -4 ---- (1)
3x-3y = -12 ---- (2)
Multiply eqn (1) by 3 and eqn (2) by 4 and add
you get 15x = -60
x= -4 and y=0
2007-05-06 18:03:35 · answer #1 · answered by sandysurd 2 · 0⤊ 0⤋
You subtract 4y from both sides of the first equation and you get x = -4 - 4y. Then you plug in that equation into the second one so you get 3(-4 -4y) - 3y = -12. You finish that up and you get y. Then you take that and plug it into one of the two equations and you'll get x.
2007-05-06 18:07:28 · answer #2 · answered by kimuzukashii 2 · 0⤊ 0⤋
from 1:- x= -4y-4
substitute in 2:-
3(-4y-4)-3y=-12
-12y-12-3y=-12
-15y=0
y=0
x=-4
2007-05-06 18:06:20 · answer #3 · answered by varun aggarwal 1 · 0⤊ 0⤋
x+4y= -4.................(1)
3x-3y=-12...................(2)
from euation 1st
x= -4-4y...............(3)
put x= -4-4y in equation(2)
3(-4-4y)-3y=-12
-12-12y-3y= -12
-15y= 0
than value of y=0
put value of y=0 in eqation 1st
x+4(0)=-4
x= -4
[x= -4 , y= 0 ]answers
2007-05-06 18:39:26 · answer #4 · answered by ANJU R 2 · 0⤊ 0⤋
x + 4y = - 4
3x - 3y = - 12
3x + 12y = - 12
15y = 0
y = 0
x = - 4
oops, by substitution
x = - 4y - 4
x - y = - 4
- 4y - 4 - y = - 4
- 5y = 0
y = 0
x = - 4
2007-05-06 18:08:56 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋
x+4y=-4 3x-3y=-12
x+4y=-4
x=-4-4y
3x-3y=-12
3(-4-4y)-3y=-12
-12-12y-3y=-12
-15y=-12+12
-15y=0
y=0
x+4y=-4
x+4(0)=-4
x+0=-4
x=-4
2007-05-06 20:46:56 · answer #6 · answered by sam 3 · 0⤊ 0⤋