10% patients die from a certain disease. 5 patients have the disease, what is the chance 2 patients will die?

Question

here are the possible solutions....

.0729

.5905

.9914

.8761

or is it none of these ?

Answer 1

It's:

(0.1)^2 * (0.9)^3 * (5! / (2! * (5-2)! ) )

That's the odds of two deaths (0.1^2) times the odds of three survivals (0.9^3), times the number of combinations of two deaths out of 5 people (5!/(2!3!)).

That calculates out to 0.0729, which matches the first answer in your list.

Answer 2

Each patient represents 20%. I should think the answer is half, .5 of a person.
Okay, I think I read the question wrong initially. My second thought is none of these are correct.

Answer 3

10% is one in ten. That means that .5 (1/2) a person out of five will die. Technically, none of those answers are correct.

Answer 4

exciting. per chance the decrease libido of growing old adult males is Nature's way of telling them they should be making way for youthful, more fit sperm and concentrating particularly on providing cloth aspects for the ensuing offspring. or per chance Nature would not quite care even if older or youthful adult males and females have little ones. Sighs.