Percentages of KOH and KCL in the original mixture [Help]?

Question

A 5.00 gram sample of a dry mixture of potassium hydroxide, potassium carbonate, and potassium chloride is reacted with 0.100 liter of 2.00 molar HCl solution.
A 249 milliliter sample of dry carbon dioxide gas, measured at 22 degrees Celsius and 740 torr, is obtained from this reaction. What is the percentage of potassium carbonate in the mixture?
The excess hydrochloric acid is found by titration to be chemically equivalent to 86.6 milliliters of 1.5 molar sodium hydroxide. What are the percentages of potassium hydroxide and of potassium chloride in the original mixture?


I figured out the first part for th percentage of K2CO3 which is 27.6%, i think.

But I dont understand the second part. I know I started with .100 liters of 2.0 molar HCl solution(.200mol). And now the last part says i ahve an excess of HCL which is equal to .0866L of 1.50 Molars HCL (.130mol).

From there I dont know what I should do to get the percentages of KOH and KCl. Help please.

Answer 1

Find out the moles of HCl that were consumed by K2CO3 and KOH.