What is the inverse of y=(x-2)/(x+1)?

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What is the inverse of y=(x-2)/(x+1) done out algebraically by swapping the x's and y's

2007-05-06 16:37:58 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

solve for y. x=(y-2)/(y+1)

2007-05-06 16:46:34 · update #1

x = (y-2) / (y+1)
<=> x (y+1) = y-2
<=> xy + x = y - 2
<=> xy - y = -x - 2
<=> y(x-1) = -(x + 2)
<=> y = -(x+2)/(x-1)

2007-05-06 16:46:21 · answer #1 · answered by Scarlet Manuka 7 · 1⤊ 0⤋

simply
y^-1 = (x+1)/(x-2)

2007-05-06 23:45:18 · answer #2 · answered by Maan_palaboy 2 · 0⤊ 1⤋

Well, I've already phoned a friend...Can I use the 50/50

2007-05-06 23:49:32 · answer #3 · answered by DonGo 2 · 0⤊ 0⤋