COuld someone please help? Thanks a bunch
To how much water should 50. mL of 12 M hydrochloric acid be added top produce a 4.0 M solution?
I have no clue where to start from. Im guessing 50 mL is the V1 and 12 M is M1 and 4.0 M is M2 but what do i do?
Could you please show how to do this problem. Thanks a bunch.
Thanks a bunch to who help me really appreciate it.
2007-05-06 16:01:34 · 2 answers · asked by sk8er_ace23 1 in Science & Mathematics ➔ Chemistry
Yup, you're right. M1V1 is for the original/ stock solution, while M2V2 is for the new solution or the solution you're making.
M1V1 = M2V2
V2 = M1V1/ M2
mL water = V2 - V1
2007-05-06 20:47:08 · answer #1 · answered by zanekevin13 4 · 0⤊ 0⤋
You are almost there.
V1M1 = V2M2
You have all the pieces. Just solve for V2
2007-05-06 23:08:11 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋