One diagonal of a rhombus is 12 cm long and its area is 120 cm^2. Find the length of a side of the rhombus!
2007-05-06 15:40:08 · 4 answers · asked by 2 days after my B day :) 2 in Science & Mathematics ➔ Mathematics
120= 12*x/2
or12x=240 so x=20--the other diagonal.
Therefore, since the diangonals are perpendicular bisectors, 6^2+10^2=c^2
or 36+100=c^2
136=c^2
c=11.66 each side has this length.
2007-05-06 15:48:36 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
Area of rhombus = half product of diagonals
1/2.a.b = 120
a=12
b= 20
Diagonals bisect each other at 90 degrees.
Length of half diagonals = 6, 10
By Pythagoras Theorem, length of 1 side of the rhombus = sqrt(6^2+10^2) = sqrt(136)
=11.66cm (approx)
2007-05-06 15:48:18 · answer #2 · answered by gudspeling 7 · 0⤊ 0⤋
Area = 1/2Dd
120=1/2(12)d
d=20
by
pythagorean theorem:
s = √ 10^2+6^2
s = 11.66 cm
2007-05-06 15:56:13 · answer #3 · answered by Maan_palaboy 2 · 0⤊ 0⤋
how the hell is this zoology. i refuse to answer your question bc of your sheer stupidity
2016-05-17 07:07:18 · answer #4 · answered by inocencia 3 · 0⤊ 0⤋