a. (x+y+3)(x-y+3)
b. (x-y+3)(x+y-3)
c. (x+y+3)(x-y-3)
d. (x-y-3)(y-x+3)
2007-05-06 15:08:57 · 5 answers · asked by miss tiramissyou 1 in Science & Mathematics ➔ Mathematics
x^2 - y^2 - 9 - 6y
= x^2 - (y^2 + 6y + 9)
= x^2 - (y+3)^2
= (x - (y+3)) (x + (y+3))
= (x - y - 3)(x + y + 3).
So (c) is correct.
2007-05-06 15:13:28 · answer #1 · answered by Scarlet Manuka 7 · 1⤊ 0⤋
First, upload some words which will make the levels in x and y a perfect sq. trinomial, and regardless of you upload on the left side would be additionally extra on the different side. that is going to grow to be x^2 - 4x + 4 + y^2 + 6y + 9 + 3 - 3 = 0 + 4 + 9 - 3. Then simplify, (x - 2)^2 + (y + 3)^2 = 10. So the middle is at (2, -3), radius is valuable sq. root of 10.
2016-10-14 23:18:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Rearranging we get
x^2 - (y^2 + 6y +9) = x^2 - (y + 3)^2
Using the fact that a^2 - b^2 = (a + b)(a - b), and applying it to this expression we get the factorization
(x + y + 3)(x - (y + 3)) = (x + y + 3)(x - y - 3) , i.e answer c.
2007-05-06 15:17:21 · answer #3 · answered by Bazz 4 · 0⤊ 0⤋
It's a difference of squares.
x^2-(y+3)^2
=[x-(y+3)][x+(y+3)]
=(x-y-3)(x+y+3)
2007-05-06 15:21:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋
B
2007-05-06 15:14:15 · answer #5 · answered by bruinfan 7 · 0⤊ 1⤋