how do you figure out ln(2t)=8?

Answer 1

Raise each side as a power of e to get rid of the ln:

e^(ln 2t) = e^8

2t = e^8

t = (e^8)/2

Answer 2

ln (2t)=8 take ecponential of each side
2t=e^8 divide both sides by 2
t=1/2 e^8=1490.48

Answer 3

If ln(2t) = 8, this means that 2t = e^8, so t = (1/2)e^8

Answer 4

Start reversing the operations.

Raise e to the power of both sides and get: e^(ln(2t)) = e^8

That simplifies to: 2t = e^8

Divide by 2 on both sides: t = (e^8)/2

Answer 5

divide the 8 by 2 then u get t=4

Answer 6

ln(2t)=8
e^8 = 2t
(e^8)/2 = t
1490.478994

Answer 7

(t) is your variable. (2t) would be 2 times T, which is your variable. Therefore, you would move the two to the opposite side by dividing it by BOTH sides, since what you do to one side you must do to the other. Therefore, on the left, the 2's would cancel, and on the right, the eight would be divided by two equaling four.
Therefore, you have t=4.

Answer 8

raise e to each side...

e^(ln(2t))=e^8

e^ln(x)=x soooo

2t=e^8

divide each side by 2 to get

t = (e^8)/2

Answer 9

ln(y)=x means y=exp(x )
ln(2t)=8
2t=exp(8)
t=(1/2)exp(8)
=1490.5 (approx)

Answer 10

easy.
ln(2t) = 8
exp(ln(2t)) = exp(8)
2t = exp(8)
t = exp(8)/2