Don't answer these unless ur sure and plz show all work:
Simplify the following
a.(x^2y)(x^3y)(x)
b.(-2a^2b^3)^2(ab)(-a^4b^5)
c.((2x^2y)^2+(-3x^4y^2)-38
d.(3a^4b^5)^2(ab)(-a^9b^5)
e.(-2m^2n^2)(4mn)^2 divided by (2m^2n^3)^3
f.12x^2y divided by 24xy
2007-05-06 11:53:04 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a. x^6y^2
b. (4a^4b^6)*(ab)(-a^4b^5)=-4a^9b^12
Hope this gets you started...
2007-05-06 11:58:36 · answer #1 · answered by bruinfan 7 · 0⤊ 1⤋
First off you should be a little more specific with your brackets. You possibly wrote 2 different math equations. For the first one you wrote (x^2y)(x^3y)(x) but I'm going to assume you meant (x^(2)y)(x^(3)y)(x).
a. x^(6)y^2
b. -4a^(9)b^(12)
c.x^(4)y^(2)-38
d. -9a^(18)b^(16)
e. -4/[m^(2)n^(5)]
f. x/2
To simplify these equations I just used the exponent laws. Here is most of them:
1. When multiplying numbers with the same base add the exponents together. IE x^3 multiplied by x^4 = x^7
2. When dividing exponents you subtract the exponents. IE x^5 divided by x^3 = x^2
3. When a number has an exponent to the power of another number multiply the exponents. IE (x^2)^3 = x^6
4. When adding or subtracting variables you may only do it if it has a common base. IE 3xy^2-2xy^2= xy^2
Those are the main things I used to solve those equations.
2007-05-06 19:58:56 · answer #2 · answered by Paulk 2 · 0⤊ 0⤋
Seems like someone needs to do their own homework... Nice try!
2007-05-06 19:01:13 · answer #3 · answered by xinerevelle 3 · 0⤊ 0⤋
haha glad im not in highschool anymore, lol
2007-05-06 18:55:53 · answer #4 · answered by Sara 2 · 0⤊ 0⤋
does ANYone pay attention in math class???....geez
2007-05-06 19:01:29 · answer #5 · answered by AM 3 · 0⤊ 0⤋