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Find the value of?

lim (sqrt x+7) -3 / 2(x-2)
x->2

2007-05-06 09:43:15 · 1 answers · asked by ph103 1 in Science & Mathematics ➔ Mathematics

1 answers

Since this is in 0/0 form, use L'Hopital's rule:
lim(x->2) (√(x + 7) - 3) / 2(x-2)
= lim(x->2) (1/2) (x + 7)^(-1/2) / 2
= (1/2) (1/√9) / 2
= 1/12.

2007-05-06 14:33:32 · answer #1 · answered by Scarlet Manuka 7 · 1⤊ 0⤋

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