Determine if the limit?

1 ⤊

Determine if the limit?

lim 3sin5x-9x / x
x->0

2007-05-06 09:40:20 · 3 answers · asked by ph103 1 in Science & Mathematics ➔ Mathematics

3 answers

You can apply l'Hopital's Rule and take the derivative of the top and the derivative of the bottom. Then evaluate the limit at 0.

(15cos5x - 9) / 1

(15cos 5(0) - 9)

15 *1 - 9

6

2007-05-06 09:50:42 · answer #1 · answered by MathMan 2 · 1⤊ 0⤋

lim 3sin5x-9x / x = lim [3(sin5x/x) - 9] = 15 - 9 = 6
x->0

2007-05-06 16:57:38 · answer #2 · answered by a_ebnlhaitham 6 · 0⤊ 0⤋

as lim sin(5x)/x= 5 the limit is 6

2007-05-06 16:46:47 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋