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2 answers

Use integration by parts with u=x and dv=sin2x and rewrite. You should receive the answer of -pi/2.

2007-05-06 09:18:46 · answer #1 · answered by Anonymous · 0 0

Int x sin(2x) dx = -1/2x* cos(2x) +1/2Int cos(2x)dx =
-1/2 x*cos(2x)+1/4 sin(2x) between (0,pi)
= -1/2*pi

2007-05-06 16:22:22 · answer #2 · answered by santmann2002 7 · 0 0

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