2007-05-06 08:29:48 · 4 answers · asked by jacque c 1 in Science & Mathematics ➔ Chemistry
Molarity = moles / L
moles = molarity x L = 3.24 x 0.250 = 0.81
Molecular mass KNO3 = 101.1 g/mol
101.1 g/mol x 0.81 mol = 81.9 g
2007-05-06 08:36:37 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Atomic weights: K=39 N=14 O=16 KNO3=101
Let solution be called S.
250mLS x 3.24molKNO3/1000mLS x 101gKNO3/1molKNO3 = 81.8gKNO3
2007-05-06 15:38:01 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
3.24 M * .250 L = moles of KNO3.
moles KNO3/[molality (moles/kg) KNO3] = mass KNO3
(I'm not doing the math for you)
-Bill
2007-05-06 15:38:45 · answer #3 · answered by Bill 4 · 0⤊ 0⤋
ok, well molarity (M)=moles/L, and u have M and mL
convert mL to L (ie: 250*10^(-3). and u knw moles= mass/molar mass...
3.24=mol/0.25L
mol=0.81
molar mass KNO3=101.10g/mol
therefore: mass=moles*molar mass
=0.81*101.10=81.89g
2007-05-06 15:43:19 · answer #4 · answered by bushbabyhmb 2 · 0⤊ 0⤋