Thanks for your help
2007-05-06 07:39:08 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
+ 6
In compounds oxigen is generally assigned the oxidation number - 2.
( - 2 ) x 7 = - 14
For charged species the sum of oxidation number of each kind of atom adds up to the net charge on the ion.
- 14 +2 = - 12
12 /2 = 6
2007-05-06 07:44:11 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Well you start by putting the problem into an equation :
2*x + 7*(-2) = -2 (Where x is the oxidation number of Cr)
x = 6
Evidently it is not 7 because that would make the molecule neutral not anionic :
7*2 + 7*(-2) = 0
2007-05-06 07:45:11 · answer #2 · answered by Daniel F 2 · 0⤊ 0⤋
+6
2 x +6 = 12 for the Cr's
7 x -2 = -14 for the O's
= -2 for the charge on the ion
2007-05-06 07:46:35 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋
yep.. its +6
2007-05-06 07:45:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋