Suppose we let the reaction 2SO2(g)+O2(g)=2SO3(g) come to equilibrium.?

Question

Then we decrease the total pressure by increasing the volume of the container. What will be the effect on the amount of SO3(g) present?
1. It doesn't change.
2. The question cannot be answered without some knowledge of the value of /\H.
3. The question cannot be answered without some knowledge of the value of Kc or Kp.
4. It increases.
5. It decreases.

Answer 1

Decreasing the pressure will favor the side that has more moles. That would be the left side

Answer 2

3. decreases. while the stress decreases, the device responds in this sort of way as to partly counteract the decrease by utilising attempting to enhance the stress. The device will enhance the stress by utilising transforming into extra debris (reactants). while extra reactants are formed, the quantity of product, SO3, decreases.

Answer 3

1+1 is my only option

Answer 4

5- it will decrease i think