how do we prove that the shortest distance between a point and a line is the perpendicular distance between that point and the line.
2007-05-06 04:16:31 · 2 answers · asked by erdf 1 in Science & Mathematics ➔ Mathematics
If you take anothe point of the line the three points forma a right angle triangle with the perpendicular distance a leg and the other distance the hypothenuse > any leg
2007-05-06 04:26:56 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
First make this one fraction, the multiplcation sign does not result the equation, (a^3 b^2 a^6 b^5)(9e^-a million f e^-a million f^3). Then combine like words, to try this upload the exponents above an identical letter so a^-3 and a^6 simplifies to a^3 (be valuable to characteristic those only in the numerator, then only in the denominator (a^3)/(a^4) does not equivalent a^7). you need to get (a^3 b^7)/(e^4 f^4). it is simplified, some math e book anticipate you to place each and all the numbers in the numerator nevertheless, to try this, multiply the backside fee's exponents by potential of -a million so e^4 will become e^-4, you will get a^3 b^7 e^-4 f^-4. wish this facilitates :)
2016-10-14 22:14:58 · answer #2 · answered by Anonymous · 0⤊ 0⤋