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One number is 6 more than another. If the sum of the smaller number and 3 times the larger number is 34, find the two numbers

2007-05-06 02:31:37 · 10 answers · asked by david v 1 in Science & Mathematics Mathematics

10 answers

y=x+6
x+3y=34
x+3(x+6)=34
x+3x+18=34
4x=16
x=4
y=10

2007-05-06 02:35:36 · answer #1 · answered by gudspeling 7 · 2 0

Express these concepts algebraically:

One number, x, is 6 more than another number, y:
x = y + 6.

The sum of the smaller number, y, and 3 times the larger number, x, is 34:

y + 3x = 34.

Rearrange the first equation: y = x - 6.

Substitute y for x - 6 in the second equation:
(x - 6) + 3x = 34
4x - 6 = 34
4x = 40

x = 10

If x = 10, y + 6 = 10, so y = 4

2007-05-06 02:38:47 · answer #2 · answered by Ian I 4 · 0 0

4 and 10 and here is how to do it, step by step with an explanation.

Let the number be represented by R.

Bread the problem up into parts and read each section carefully.

3 times the larger number is 34 (3R = 34)

If the sum of the smaller number (adding, and the other number is smaller)

One number is 6 more than another - the larger number is 6 more so the smaller number must be 6 less
- if the smaller number is 6 less than the smaller number must be R - 6

If the smaller number is (R - 6) and the larger number is (R) then the sum of the smaller and 3 times the larger has to be
(R-6) + (3R) and this all equal 34.

OK Lets find the value of R

( 3R + R-6 ) = 34
4R - 6 = 34
4R -6 + 6 = 34 + 6
4R = 40
R = 40/4
R = 10

The other number is R - 6 = 4
The two numbers are 4 and 10.

Lets check to see if we are right.

If the sum of the smaller number and 3 times the larger number is 34,

4 + (3 x 10) = 34
4 + 30 = 34
34 = 34

2007-05-06 02:34:20 · answer #3 · answered by Critters 7 · 0 0

10 and 4

2007-05-06 02:35:26 · answer #4 · answered by Anonymous · 0 0

You could try solving it logically. The bigger number - 6 is the smaller number. 3 times the big number + the small number=34.
3x+y=34.
Then x would be 10, y would be 4. Substitute to see if you got it right.

2007-05-06 02:39:33 · answer #5 · answered by Avatar Unknown 2 · 0 0

smaller number = x
larger number = x + 6
x + 3(x+6) = 34
x + 3x +18 = 34
4x + 16
x = 4
x+6 = 4 + 6 = 10

the numbers are 4 ad 10

2007-05-06 03:11:26 · answer #6 · answered by Gina C 2 · 0 0

Let X be the larger no. and Y the smaller no.
X = 6+Y
Y + 3X = 34
Y + 3(6+Y) = 34
Y + 18 + 3Y = 34
4Y = 34 - 18
4Y = 16
Y = 4
X = 10

2007-05-06 02:39:19 · answer #7 · answered by Sandy 7 · 0 0

10 & 4

2007-05-06 02:34:54 · answer #8 · answered by elsewhere_for_eight_minutes 3 · 0 0

permit one style be x. different style is 3 below x = x - 3. 4 circumstances smaller style minus thrice extra suitable style = 4(x - 3) - 3x = 4 => 4x - 12 - 3x = 4 => x - 12 = 4 => x = 4 + 12 = sixteen => x - 3 = sixteen - 3 = 13. in this occasion numbers are 13 and sixteen.

2016-10-14 22:08:46 · answer #9 · answered by ? 4 · 0 0

x=y+6
y+3x=34


y+(3y+18)=34
4y=34-18
4y= 16

y=4
x=4+6=10

2007-05-06 02:36:44 · answer #10 · answered by iyiogrenci 6 · 0 0

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