3x⁻¹/² -4 = 0
thanks
2007-05-06 00:33:54 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sorry it is 3x^-1/2 - 4 = 0
2007-05-06 00:40:37 · update #1
3x^-1/2 - 4 = 0
the index (-1/2) is the same as the square root of. and the minus sign just puts it as the denominator.
and the minus four goes to the other side of the equals sign.
3/(root x) = 4
the denominators change places.
3/4 = root x
x = 9/16 when you square 3/4.
sorry if its wrong ^^" although im pretty sure its not
2007-05-06 00:50:15 · answer #1 · answered by ` crystal tears . 2 · 0⤊ 0⤋
7
2007-05-06 00:40:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
heres a start,
the roots of ax(squared)+bx +c = 0 are x = -b +-(square root of) b(squared) - 4 ac
divided by
2a
2007-05-06 00:51:15 · answer #3 · answered by booja 2 · 0⤊ 0⤋
That's too easy,
3*x^(-0.5) -4 =0
3/(x^0.5) - 4=0
3/(x^0.5) = 4
1/(x^0.5)=4/3
inverting both sides:
x^(0.5) = 3/4
and then:
x= (3/4)^2
x=9/16
Be Succeed,
Babax.
2007-05-06 00:54:29 · answer #4 · answered by Babax 3 · 0⤊ 0⤋
3x^-1/2=4
x^-1/2=4/3
1/x=1.4^2
x=1/1.96
x=0.51
2007-05-06 02:07:24 · answer #5 · answered by moon r 2 · 0⤊ 0⤋
Solve it youself.I did my own homework.
2007-05-06 00:43:39 · answer #6 · answered by taxed till i die,and then some. 7 · 0⤊ 1⤋
umm, well i definetly know it's a number, hmmm
probably a number between -â and â.
2007-05-06 00:44:33 · answer #7 · answered by brodie 2 · 0⤊ 1⤋
what is all that squiggly stuff?
2007-05-06 00:38:59 · answer #8 · answered by tom4bucs 7 · 0⤊ 0⤋