sine and cos of angle -5pi/3 using standard unit circle....?

Answer 1

The angle -5π/3 is conterminal with π/3. So the sine and cosine of -5π/3 are the same as the sine and cosine of π/3.

sin(-5π/3) = sin(π/3) = √3/2

cos(-5π/3) = cos(π/3) = 1/2

Answer 2

Draw a caricature... part AB is opposite attitude C (and is the hypotenuse)=7 part AC is opposite attitude B and adjoining to attitude A=2sqrt(6) part BC is opposite attitude A and adjoining to attitude B=5 you are able to %. even with ratio choose for attitude B; merely be effective you tournament up the corresponding sides sin B = opp / hyp = AC / AB = 2sqrt(6) / 7 B = arc sin 2sqrt(6)/7 cos B = adj / hyp = BC / AB = 5 / 7 B = arc cos 5/7 tan B = opp / adj = AC / BC = 2sqrt(6)/7 B = arc tan 2sqrt(6) / 7 a number of those provides you an similar answer (B = 40 4.40 2 degrees) (and hence A = 40 5.fifty 8 degrees to envision with arc sin 5/7)

Answer 3

sin (-5pi/3) = [square root (3)]/2
cos(-5pi/3) = 1/2

-5pi/3 is the same as -pi/3, and if you draw the triangle, the x value is 1/2, the y value is -[squareroot(3)]/2, and the hypotenuse is 1.

Answer 4

pi/3 in standars unit circle equals 60'.
5pi/3 = 300'
-5pi/3 =-300'=+60 ' = +pi/3
sin(pi/3)=sqrt (3)/2
cos(pi/3) = 1/2

Answer 5

-5π/3 gives the same results as 2π - 5π/3

2π - 5π/3 = π/3

sin -5π/3 = sin π/3 = √3/2

cos -5π/3 = cos π/3 = 1/2

Answer 6

(- 5π/3) = π/3
cos π/3 = 1/2
sin π/3 = √3 / 2