2007-05-05 21:33:35 · 5 answers · asked by Anthony L 1 in Science & Mathematics ➔ Chemistry
15.9994*100/(15.9994 + 22.989770) = 41.04%
2007-05-05 21:55:35 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
First you should calculate the molecular mass of sodium peroxide:
2(23) +2(16) =78 grams. Then you calculate the molecular mass of 2 oxygen atoms: 16x 2= 32 grams.
Therefore, % of oxygen in sodium peroxide = 32/78 x 100
=41.03 %
2007-05-06 05:57:29 · answer #2 · answered by hans 1 · 0⤊ 0⤋
percent by mass = Mass of oxygen/total mass
so 32.0/78
2007-05-06 04:41:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋
41.04% i think.. not sure though.
2007-05-06 04:40:45 · answer #4 · answered by helping_hand 2 · 0⤊ 0⤋
41.03%
2007-05-06 04:36:59 · answer #5 · answered by pigley 4 · 0⤊ 0⤋