A plane travelling 600miles/hr is 30 miles from an airport at 4:58p.m.At what time will it arrive at airport?

Question

word problem of time management

Answer 1

It travels 600 miles in 60 mins
so it travels 30 miles in 30x60/600 = 3 mins
It will arrive at 4.58 + 0.03 = 5.01 pm

Then you wait 1 hr to collect your luggage!

Answer 2

The plane must slow down (from 600 to 0 when it has landed).
Let's agree it decelerates at a constant rate:
a=-k (k>0)
v=600-kt
x=600t-(kt^2)/2
x must be 30 at the end
=> 30=600t-(kt^2)/2
=> kt^2-1200t+60=0
delta=1440000-240k
2 solutions:
T=(1200-sqrt(1440000-240k))/(2k) (<0, so not valid ) or
T=(1200+sqrt(1440000-240k))/(2k) (>0, so valid)

In the mean time, the speed must go down to 0, therefore k=600/T
=>2kT=1200+sqrt(1440000-240k)
=>1200=1200+sqrt(1440000-144000/T)
=>0=sqrt(1440000-144000/T)
=>0=120 x sqrt(100-10/T)
=> 0=sqrt(100-10/T)
=> 0=100-10/T
=> T=1/10h
=> T=6min

Another view would have been: the average speed on the disance would be 300 miles/h, therefore, it needs 6 min to do 30 miles. Which is a lot simpler to get to the same result, but I like making things complicated!
Thankfully, I didn't take into consideration the wind, the turbulences and if it has had the "go" from air control or not! ;-)

It will arrive at 5:04pm (roughly).

Answer 3

It will travel 10 miles in one miunute so it will reach airport in 3 minutes, arriving at 5.01 pm.

Answer 4

t = (30 / 600) x 60 mins
t = 3 mins
Will arrive at 5:01 pm (17:01)

Answer 5

3 minutes
5:01 PM
No airplane can do this, taxying alone will consume 5 or more minutes, landing with additional time.

Answer 6

Firstly it depends if it is flying away from the airport or towards it, but i think you mean towards it so i will answer accordingly.
T=D/S
Time=Distance/Speed
600mph=268.22478m/s
30 miles =48280.32m
T=48280.32/268.22478=179.99sec
4:58+2min,59.999=5:00.59.99p.m.

Answer 7

5.01p.m.