insert three arithmetic means between 25 and -7?

Question

please tell the whole procedure i.e. what to write in beginning etc.

Answer 1

I think you want a series.
First term is 25 and 4th term is – 7
Let the common difference be d
then 1st No. = 25
2nd No. = (25 + d)
3rd No. = (25 + d) + d
4th No. = (25 + d + d + d) = 25 + 3d
5th No. = (25 + 3d ) + d = 25 + 4d
& 5th No. is – 7
therefore
25 + 4d = – 7
4d = – 8
common difference is – 8
So the series is 25, 17, 9, 1, 7
So the numbers introduced are 17, 9, 1

Answer 2

Your question, as worded, is unclear. There is only one mean between two numbers, the midpoint (in this case 16). If u take the total distance, it is 32 (25 - - 7 = 32). If u start at point A (25) and procede to point B (-7) u move 32 units. If u wish to place three equidistant points along the way, they are eight units apart.
(32divided by four since three points along the way divides the trip into four equal parts) So, the points would be at 1, 9, and 17. (start at -7 and add eight or start at 25 and subtract 8)

Answer 3

25 a b c -7

-7=25+4d

d=-32/4=-8

a=25+1(-8)=17
b=25+2(-8)=9
c=25+3(-8)=1

-7=25+4(-8)=-7

Answer: 17, 9, 1

Answer 4

let the three terms be a-d,a,a+d
so the series becomes
-7,a-d,a,a+d and 25

since for any am seris wid a,b,c.....2b=a+c

therefore

a+2d=25
a-2d=-7

therefore a=9 and d=8

so.the series becomes -7,1,9,17,25

Answer 5

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