Quadratic equation, help?

Question

-.6x^2 - 1.3x = .1

Can u solve using quadratic equation, and answer in exact numbers? THanks

Answer 1

yes you can..

u just subtract .1 from both sides.. and there you go u have
a. -.6
b. 1.3
c. -.1

Answer 2

-.6x^2 - 1.3x = .1

I hate working with decimals as factors, don’t you?....
Multiply both sides by 10.
-6x² -13x =1
Add -1 to both sides
-6x² - 13x – 1 = 0
Multiply both sides by -1
6x² + 13x + 1 = 0


This doesn’t factor.
You have to use the quadratic formula
x = [-b±√(b²-4ac)]/2a where a=6, b=13, and c=1
You get something divided by 12… not likely to be an exact value
x = {-13±√[13²-4(6)(1))]}/2(6)
= {-13±√[169-24)]}/12
= {-13±√(145)}/12
√(145) is not pretty
So the solutions are (-13+√145)/12 and (-13-√145)/12. That's as far as I would go.

But, if you really want a numerical answer, you can do it on a calculator as easily as I can. Take the square root of145, subtract 13 from it and divide the answer by 12... that's one. Take the square root of 145 again, change the sign. Again subtract 13, and divide that answer by 12... that's the other.

Answer 3

-.6x^2 - 1.3x = .1
-6x^2 - 13x-1=0
a=-6
b=-13
c=-1

x1=(13-sqrt(145))/(-12)

x1=(13+sqrt(145))/(-12)

Answer 4

x = -2.0868, -.0799
Work shown here: http://img400.imageshack.us/img400/9428/workmh2.jpg