f(x)=x to the third power+11x squared-150x-1512; -14?

Question

Given one zero of the polynomial function, find the other zero

Answer 1

f(x)=x^3+11x^2-150x-1512

=(x+14)(x^2-3x-108)

=(x+14)(x+9)(x-12)

the other zeros are -9 and 12

Answer 2

If f(x) = x^3 +11x^2 - 150x - 1512 and a zero of f(x) is x = -14,
then (x + 14) is a factor of f(x). Divide f(x) by (x + 14), and get the quotient x^2 - 3x - 108. So, f(x)=0 can be written as (x + 14)(x^2 - 3x - 108) = 0. Factor the quadratic factor to get (x + 14)(x +9)(x -12) =0. By the zero product law, setting each factor equal to zero, you get x + 14 = 0 or x + 9 =0 or x - 12 = 0. So, the zeros of f(x) are -14, -9, and 12.

Answer 3

First I wish to tell you that ^ mean power so,
The equation is x^3+11x^2-150x-1512
One of the answer is -14, so make it like this by using Horner division.

1 14/ 1 11 -150 -1512 \
1 14 *
--------- -
-3 -150
-3 -42 *
----------- -
-108 -1512
-108 -1512 *
------------------ -
0 0

By taking the front of each line with *, you will get an equation which is quadratic : x^2-3x-108 =0
A quadratic equation is solvable using the ABC technique and you will got -9 and 12 as the answer.

There is also ABCD technique for cubic equation, which can be used without knowing any root of it. Contact me if you want it.

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Answer 4

f(x)=x to the third power+11x squared-150x-1512; -14

This is clearly wrong, and to be honest if you havent grasped the basics WE the people of Yahoo cant help you !!!

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