major axis endpoints (0,+ or -6), minor axis length4?

Question

a)x^2/36 +y^2/4 =1
b)x^2/2 +y^2/6 =1
c)x^2/6 +y^2/2 =1
d)y^2/36 +x^2/4 =1

Answer 1

Could be A) or C) because either x or y could have the major and minor axis.

Answer 2

The standard equation of an ellipse centered at the origin is (x^2)/(a^2) + (y^2)/(b^2) = 1 where the major axis is horizontal or (x^2)/(b^2) + (y^2)/(a^2) = 1 where the major axis is vertical. "a" is half the length of the major (longer) axis and "b" is half the length of the minor (shorter) axis. In this problem, the major axis with endpoints (0,6) and (0,-6) has length 12 and is vertical. So, the answer is D.

Answer 3

ellipses are in the form

x^2 / (a^2) + y^2 / (b^2) = 1

a and b are either half of the major or minor axes, depending on the which axis the major axis is parallel to.

In this case, the major axis is on the y-axis, and has length of 12.
so b=6, and a = 2

so the answer is D

Answer 4

d)y^2/36 +x^2/4 =1

Answer 5

(d)

Major axis is in the y direction (numerr under y must be larger)

denominator must be intercept^2
6^2 and then
for x =====> 1/2 of x ===> 2, then 2^2 = 4

:)